(x^2+3x+5)(4x^2+3)=0

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Solution for (x^2+3x+5)(4x^2+3)=0 equation:


Simplifying
(x2 + 3x + 5)(4x2 + 3) = 0

Reorder the terms:
(5 + 3x + x2)(4x2 + 3) = 0

Reorder the terms:
(5 + 3x + x2)(3 + 4x2) = 0

Multiply (5 + 3x + x2) * (3 + 4x2)
(5(3 + 4x2) + 3x * (3 + 4x2) + x2(3 + 4x2)) = 0
((3 * 5 + 4x2 * 5) + 3x * (3 + 4x2) + x2(3 + 4x2)) = 0
((15 + 20x2) + 3x * (3 + 4x2) + x2(3 + 4x2)) = 0
(15 + 20x2 + (3 * 3x + 4x2 * 3x) + x2(3 + 4x2)) = 0
(15 + 20x2 + (9x + 12x3) + x2(3 + 4x2)) = 0
(15 + 20x2 + 9x + 12x3 + (3 * x2 + 4x2 * x2)) = 0
(15 + 20x2 + 9x + 12x3 + (3x2 + 4x4)) = 0

Reorder the terms:
(15 + 9x + 20x2 + 3x2 + 12x3 + 4x4) = 0

Combine like terms: 20x2 + 3x2 = 23x2
(15 + 9x + 23x2 + 12x3 + 4x4) = 0

Solving
15 + 9x + 23x2 + 12x3 + 4x4 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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